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If C=r+7 and D=-2r+3, find an expression that equals 2C−D in standard form.

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If [tex]\rm{C = r + 7}[/tex] and [tex]\rm{D = -2r + 3}[/tex], find an expression that equals [tex]\rm{2C − D}[/tex] in standard form.

  • [tex]\Large\sf{\underline{\green{4r + 11}}}[/tex]

[tex]\\[/tex]

[tex]\huge{\red{\boxed{\gray{\mathbb{SOLUTION}}}}}[/tex]

» Given:

  • [tex]\rm{C = r + 7}[/tex]

  • [tex]\rm{D = -2r + 3}[/tex]

» We need to find the value of 2C- D. To solve this, we need to substitute the values of C & D in the expression. So,

  • [tex]\rm{2C - D}[/tex]

» Substitute the given values:

  • [tex]\rm{= 2(r + 7) - (-2r + 3)}[/tex]

» Now, follow the distributive property:

  • [tex]\rm{= 2r + 14 + 2r - 3}[/tex]

» Rearrange the terms:

  • [tex]\rm{= 2r + 2r + 14 - 3}[/tex]

» Do the required arithmetic operation:

  • [tex]\rm{= 4r + 11}[/tex]

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