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The maximum load of a beam varies directly as the breadth and the square of the depth and inversely as the length . If a beam 5m long, 2m wide and 3m deep can safely bear a load up to 720 kg, find the maximum safe load for a beam of the same material which is 4m long, 6 m wide and 3m deep.​

Sagot :

Answer:

EQUATION: m = kbd² / l909 = k(1.2)(2.4)² / (3.6)909 = k (864 / 125) / 3.

Step-by-step explanation:

EQUATION: m = kbd² / l909 = k(1.2)(2.4)² / (3.6)909 = k (864 / 125) / 3.