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Answered

A saline solution contains 0.90 g of NaCl per 100 mL of solution. What is its molarity?​

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Answer:

For example, 0.9% NaCl contains 0.9 g NaCl per 100 ml of solution or 9 g NaCl/l. This can be converted to molarity by dividing by molecular weight: 0.9% NaCl = (9g/l)/(58.5g/mole) = 0.15 M NaCl.

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