use synthetic substitution to find P(x) for each function.

1. P (3) =x³ – 3x² – x + 2
2. P (–1) = 2x³ + 2x² – 4x + 1
3. P (x) = 2x³ – 2x² – 8x + 7; x – 2
4. P(x) = x³ – 8x² – 3x + 5; 2x –1
5. P (⅖) = 10x⁴ + x³ – 12x² + 15x – 4​