Problem:
If R varies inversely as s and r=10 when S= 6 what it r when s=4?
Solution:
[tex]\[r = \frac{k}{s}\][/tex] ; where k = constant of variation
[tex]\[\begin{array}{l}10 = \frac{k}{6}\\\\10(6) = k\\\\k = 60\end{array}\][/tex]
[tex]\[r = \frac{k}{s}\][/tex]
[tex]\[\begin{array}{l}r = \frac{{60}}{4}\\\\r = 15\end{array}\][/tex]
Answer:
r = 15
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