Math 6 Module 5 Assessment

[tex]\begin{aligned}\text{A. } & 4\dfrac{7}{10} & \text{B. } & 2\dfrac{1}{8} & \text{C. } & 2\dfrac{7}{10} & \text{D. } 4\dfrac{1}{8} \end{aligned}[/tex]
[tex]\begin{aligned}4\dfrac{3}{6} \div 1\dfrac{2}{3} = \dfrac{27}{6} \div \dfrac{5}{3} = \dfrac{27}{6} \times \dfrac{3}{5} = \dfrac{81}{30} \Rightarrow \dfrac{27}{10} = 2\dfrac{7}{10} \end{aligned}[/tex].
Mathematics 6 Module 5
Pre-assessment: Multiple Choice (Item 1-4): brainly.ph/question/8785116
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Note: The answer is correct.