Answer:
Arithmetic Sequence
an = last term of the nth value
a1 = first term
n = number of terms
d = difference
GIVEN
a1=4
d=5
SOLVING
a6 = 4+(6-1)5
=4+(5)5
=4+25
=29
a7 = 4+(7-1)5
= 4+(6)5
=4+30
=34
a8 = 4+(8-1)5
=4+(7)5
=4+35
=39
a9 = 4+(9-1)5
= 4+(8)5
=4+40
=44
a10 = 4 + ( 10 - 1 ) 5
= 4 + (9) 5
= 4 + 45
= 49
Step-by-step explanation:
