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(4xy+xy²-2x-3y+1)-(x²+4y+2xy²+xy)​

Sagot :

Answer: =−xy2−x2+3xy−2x−7y+1

Step-by-step explanation:

Let's simplify step-by-step.

4xy+xy2−2x−3y+1−(x2+4y+2xy2+xy)

Distribute the Negative Sign:

=4xy+xy2−2x−3y+1+−1(x2+4y+2xy2+xy)

=4xy+xy2+−2x+−3y+1+−1x2+−1(4y)+−1(2xy2)+−1xy

=4xy+xy2+−2x+−3y+1+−x2+−4y+−2xy2+−xy

Combine Like Terms:

=4xy+xy2+−2x+−3y+1+−x2+−4y+−2xy2+−xy

=(xy2+−2xy2)+(−x2)+(4xy+−xy)+(−2x)+(−3y+−4y)+(1)

=−xy2+−x2+3xy+−2x+−7y+1

Answer:

=−xy2−x2+3xy−2x−7y+1