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A delivery truck carrying 75 cavans of rice is travelling at 10m/s. The mass of the truck and one canvas of rice is 3000kg and 50kg, respectively. The driver of the truck has a mass of 85kg. What is the magnitude of the momentum of the truck with the driver and the cavans of rice? At a certain grocery, the driver unloaded 8 cavans. What is the new momentum of the truck with the driver and the cavans of rice if the driver maintains the same speed?​

Sagot :

Answer:

p=mv

p=(3000+75⋅50)(10)=67500

s

kgm

b)

p'=(3000+(75-8)\cdot50)(10)=63500\frac{kgm}{s}p

=(3000+(75−8)⋅50)(10)=63500

s

kgm