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A 4.0-kg particle is moving horizontally with a speed of 5.0 m/s when it strikes a vertical wall. the particle rebounds with a speed of 3.0 m/s. what is the magnitude of the impulse delivered to the particle

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[QUESTION ❓]

A 4.0-kg particle is moving horizontally with a speed of 5.0 m/s when it strikes a vertical wall. the particle rebounds with a speed of 3.0 m/s. what is the magnitude of the impulse delivered to the particle?

[ANSWER]

32 kg/ms

I will help with this, then you do the rest.

impulse = change in momentum = force * time

initial momentum = 4*5 = 20

final momentum = 4*-3 = -12

change = -12 - 20 = -32

magnitude of change of momentum

= impulse

= 32

HOPE IT HELPS ☺

✳ PRIMROWES ✳

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