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Answered

What is the center and radius of a circle whose equation is given by (x-2)^2+(y+5)^2=13

Sagot :

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Answer:

An equation of the circle with center (h,k) and radius r is

(x−h)

2

+(y−k)

2

=r

2

So, comparing (x−2)

2

+(y+5)

2

=13 that is (x−2)

2

+(y−(5))

2

=13 with the above equation of circle we get:

h=2, k=−5 and r=

13

Therefore, center of the circle is (2,−5) and radius of the circle is r=

13

Step-by-step explanation:

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