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A stone is dropped from the top of the wall which is 7 m high. How long will it take for the stone to reach the ground if air resistance is neglected?​

Sagot :

Answer:

Given: vi = 0m/s

yi = 0m

yf = -7m

a = g = -9.8m/s^2

Required to find: t

Equation to be used: vf^2 = vi^2 + 2g (yf - yi) ➜ to find the final velocity

vf = vi + gt ➜ to find the time

Solution:

vf^2 = vi^2 + 2g (yf - yi)

√(vf^2 )= √(2gyf )

vf = √(2(-9.8 m/s^2)(-7m))

vf = √(-137.2m^2/s^2 )

vf = -11.71m/s

For Time:

vf = vi + gt

vf = gt

(-11.71m/s = (-9.8m/s^2)t)/(-9.8m/s^2 )

1.19s = t

t = 1.19s

Answer:

GIVEN:

Initial velocity = vi = 0

Distance travelled : S = 7m

time = t = ?

Acceleration = g = 9.8ms-²

Using 2nd Equation of motion

S = vi*t + ½g*t²

t = √(2S/g)

ANSWER: t = 1.19 seconds

This is the time to travel a distance of 7m.

Explanation:

Hope it helps!