Sagot :
Answer:
Given: vi = 0m/s
yi = 0m
yf = -7m
a = g = -9.8m/s^2
Required to find: t
Equation to be used: vf^2 = vi^2 + 2g (yf - yi) ➜ to find the final velocity
vf = vi + gt ➜ to find the time
Solution:
vf^2 = vi^2 + 2g (yf - yi)
√(vf^2 )= √(2gyf )
vf = √(2(-9.8 m/s^2)(-7m))
vf = √(-137.2m^2/s^2 )
vf = -11.71m/s
For Time:
vf = vi + gt
vf = gt
(-11.71m/s = (-9.8m/s^2)t)/(-9.8m/s^2 )
1.19s = t
t = 1.19s
Answer:
GIVEN:
Initial velocity = vi = 0
Distance travelled : S = 7m
time = t = ?
Acceleration = g = 9.8ms-²
Using 2nd Equation of motion
S = vi*t + ½g*t²
t = √(2S/g)
ANSWER: t = 1.19 seconds
This is the time to travel a distance of 7m.
Explanation:
Hope it helps!