Sagot :
SOLUTION:
[tex]\begin{aligned} \text{pH} & = \text{p}K_{\text{a}} + \text{log} \left(\frac{[\text{conjugate base}]}{[\text{acid}]}\right) \\ & = \text{p}K_{\text{a}} + \text{log} \left(\frac{[\text{HCO}_3^-]}{[\text{H}_2\text{CO}_3]}\right) \\ & = 6.4 + \text{log} \left(\frac{0.024}{0.0012}\right) \\ & = \boxed{7.7} \end{aligned}[/tex]
Hence, the pH of the blood is 7.7
[tex]\\[/tex]
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