Answer:
Volume of CO₂ : V=53.9 L
Further explanation
In general, the gas equation can be written
PV=nRT
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08205 L.atm / mol K
T = temperature, Kelvin
Given
200.5 g C₆H₁₂O₆
Temperature = 28°C+273=301 K
Pressure = 1.02 atm
Required
Volume of CO₂
Solution
Reaction
C₆H₁₂O₆(aq) ⇒ 2 C₂H₅OH(l) + 2 CO₂ (g)
mol C₆H₁₂O₆ :
= mass : molar mass
= 200.5 g : 180.16 g/mol
= 1.113
From the equation, mol CO₂ :
= 2/1 x mol C₆H₁₂O₆
= 2/1 x 1.113
= 2.226
Ideal gas law :
V=nRT/P
V=2.226 x 0.08205 x 301 /1.02
V=53.9 L
c.53.0 L
Explanation:
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