Answer:
1. A = {head, tail}, n(A) = 2 (tossing a coin)
B = {1,2,3,4,5,6}, n(B) = 6 (rolling a die)
P(A union B) = {1,2,3,4,5,6,head,tail}, n(A union B) = 8
P(A intersection B) = ∅ (since the two sample spaces have nothing in common)
2. P(n,r) = n! / (n-r)!, n = 5, r = 2
P(5,2) = 5! / (5-2)!
P(5,2) = 120 / 3!
P(5,2) = 120 / 6
P(5,2) = 20 ways
So, A = {(A,B), (B,C), (A,C),...,(A,E)}, n(A) = 20
Hope this helps. ^^
