👤
Answered

A long jumper leaves the ground at an angle of 20.0 degrees above the horizontal and at a speed of 11.0 m/s. how far does he jump in the horizontal direction

Sagot :

UNKNOWN1912IN

Answer:

Vertical initial velocity = 11 sin 20 = 3.76 m/s

Horizontal velocity = 11 cos20 = 10.34 m /s

Vertical final Velocity = 0

Time of flight = 2 * ( 11 sin 20 ) / 9.8 = 0.77 s .

Range = 0.77* 11 cos20= 7.96 m

Height = H = u^2/ 2g = 3.76^2/ ( 2*9.8) = 0.72 m

In Studier: Other Questions