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polynomial function:
pasagot plss

1.) f(×)=(×-3)(×-1)(×+1)
2.) h(×)=-×(×+2)(×-2)​


Sagot :

Answer:

f(x) has three zeros

h(x) has three zeros

Step-by-step explanation:

1. F(x) = =>7 (x-3) (x-1) (x+1) = 0

x, =3; x2=1, x3= -1

F(×) has three zeros

2. H(×) =0 => -× (×+2) (×-2) = 0

x, =0; ×2=; ×3=2

H(x) has three zeros

HOPE IT HELPS