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Find the equation of the circle in general form: With a center (1,4) and which passes through (2,6)

Sagot :

Answer:

First, compute [tex]r^{2}[/tex] using the distance formula

[tex]r^{2} =(1-2)^{2} +(4-6)^{2} =1 +4=5[/tex]

The general equation of a circle with center (h, k) and radius r is

[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]

Therefore, the answer is

[tex](x-1)^{2} +(y-4)^{2} =5[/tex]