Answer:
99polygons
2598960 sets
252 ways
Step-by-step explanation:
2. 7C3=35 , 7C4=35 ,7C5= 21, 7C6=7 , 7C7=1
Add the answer from 7C3 to 7C7 = 35+35+21+7+1 = 99 polygons
3. The 1st choice is 1 of 52.
Then 1 of 51, etc.
--> 52×51×50×49×48 = 311857200
--
But, choosing cards A,B,C,D & E is the same as B,A,D,E & C.
= 120 (5×4×3×2×1) ways to get the same 5 cards.
311857200/120 = 2598960 sets
4. We have 5 items to choose from 10 possible problems, so r = 5, n = 10. Substituting it to the formula and simplifying gives us:
= 10!/5!(10-5)!
=10!/5!5!
=10×9×8×7×6×5!/5×4×3×2×1×5!
=3×2×7×6
=252 ways
