Answer:
The mass of the given mole of CaCl_2CaCl
2
is required.
The mass of the given compound is 98.78 g.
Molar mass of CaCl_2CaCl
2
M=40.078+35.453\times 2=110.984\ \text{g/mol}M=40.078+35.453×2=110.984 g/mol
n = Number of moles = 0.89 mol
Mass is given by
\begin{gathered}m=Mn\\\Rightarrow m=110.984\times 0.89\\\Rightarrow m=98.78\ \text{g}\end{gathered}
m=Mn
⇒m=110.984×0.89
⇒m=98.78 g
The mass of the given compound is 98.78 g.
