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1. Given parallelogram MESA. if ME = 2x + 1 m and SA = x + 2 m, find the length of ME and SA​

1 Given Parallelogram MESA If ME 2x 1 M And SA X 2 M Find The Length Of ME And SA class=

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MISSRAINNEIN

Step-by-step explanation:

Given

 ME = 2x + 1 m, SA = x + 2 m

Solution

 2x + 1 = x + 2

 2x - x = 2 -1

 x = 1

 2x + 1 = 2(1) + 1 = 3

 x + 2 = (1) + 2 = 3

Answer:

 ME = 3 m

 SA = 3 m

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