[tex]\Large\color{aqua}\underline\mathbb{SUBSTITUTION \: METHOD}[/tex]
Given equations:
[tex]\begin{cases} \sf{x=5y-2} \\ \sf{x-4y=1} \end{cases}[/tex]
To use substitution method, simply replace the variable x in the equation x - 4y = 21 to 5y - 2, since it is x = 5y - 2.
[tex]\\[/tex]
- x - 4y = 1
- 5y - 2 - 4y = 1
- y - 2 = 1
- y = 1 + 2
- y = 3
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The value of y is given. Now we are going to find the value of x. Substitute the variable x in the equation x = 5y - 2 to 3.
- x = 5y - 2; y = 3
- x = 5(3) - 2
- x = 15 - 2
- x = 13
[tex]\\[/tex]
[tex]\color{blue}\underline\mathbb{ANSWER:}[/tex]
- ∴ Therefore, the two numbers are 3 and 13.
- ∴ x = 13, y = 3
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[tex]\tt\color{aqua}{9:21 \: am}[/tex]
[tex]\tt{3/4/22}[/tex]
