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Quadrilateral EFGH is a parallelogram.
If angle H = 2x and angle E = 5x + 40, find angle E.​


Sagot :

Answer:

∠H and ∠E are consecutive angles; therefore, they are supplementary angles.

∠H + ∠E = 180

[tex]2x+5x+40=180[/tex]

[tex]7x=180-40[/tex]

[tex]x=\frac{140}{7} =20[/tex]

∠E = 5x + 40 = 5(20) + 40 = 140°