Answer:
No x-intercept/zero
Step-by-step explanation:
[tex]f(x) = {x}^{2} + 1[/tex]
To find x-intercept/zero, substitute f(x) = 0
[tex]0 = {x}^{2} + 1[/tex]
Since the right hand side is always positive, the statement is false for any value of x
[tex]0 = {0}^{2} + 1[/tex]
[tex]0 = 1[/tex]
0 is not equal to 1, therefore there is no x-intercept/zero.
hope this helps :)
