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The sum of three numbers is 188. The second number is 12 larger than the first, and the third is twice as large as the second. Find the three numbers.​

Sagot :

Answer:

The numbers are 38, 50 and 100.

Step-by-step explanation:

Let x be the 1st number

x + 12 be the 2nd number

2(x+12) be the 3rd number

Sum = 188

add the three numbers and get the value of x

x + (x+12) + 2(x+12) = 188

x + x + 12 + 2x + 24 = 188

x + x + 2x = 188 - 24 - 12

4x = 152

x = 152/4

x = 38

x + 12 = 38 + 12

x + 12 = 50

2(x+ 12) = 2(38+12)

2(x +12) = 2(50)

2(x+12) = 100