A mixture of 305 g of Aluminum sulfide and 215 g of water reacted and forming dihydrogen sulfide as

one of the products as shown in the following reaction.

Al2S3 + H2O Al(OH)3 + H2S

a. Determine the limiting reactant.

b. Calculate the amount of H2S in grams that can be produced (theoretical yield).

c. If the actual yield of H2S produced experimentally was 180.75 g H2S, determine the percentage

yield of the product in the reaction.

d. How many moles of Al2S3 are there in 305 g of Al2S3?​