So here one side of a cube is given.
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And we have to find Amount of water we can fill in that cube. that means , we have to find volume of a cube.
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We know:-
[tex] \bigstar \boxed{ \rm volume \: of \: cube = {side}^{3} }[/tex]
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So:-
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[tex] \dashrightarrow\sf volume \: of \: cube = {side}^{3} \\ [/tex]
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[tex] \dashrightarrow\sf volume \: of \: cube = {6}^{3} \\ [/tex]
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[tex] \dashrightarrow\sf volume \: of \: cube = 6 \times 6 \times 6 \\ [/tex]
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[tex] \dashrightarrow\sf volume \: of \: cube = \underbrace{ 6 \times 6 }\times 6 \\ [/tex]
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[tex] \dashrightarrow\sf volume \: of \: cube = 36\times 6 \\ [/tex]
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[tex] \dashrightarrow\bold{ volume \: of \: cube = \underline{ \underline{216 \: \: m}}} \\ [/tex]
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know more:-
[tex]\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc}\small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bold{CSA_{(cylinder)} = 2\pi \: rh}\\ \\\bigstar \: \bold{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bold{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bold{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar\: \bold{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bold{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bold{Volume_{(cube)} ={(side)}^{3} }\\ \\ \bigstar \: \bold{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bold{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\\bigstar \: \bold{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bold{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bold{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
