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solve for the resultant force of an object thrown 7N west, then 55N 35° south of Eastand finally 50N north. Use the component method​

Sagot :

Answer:

Determine the sum of the vertical and horizontal components.

[tex]R_{v} =-55sin(35)+50=18.45N[/tex]

[tex]R_{h} =-7+55cos(35)=38.05N[/tex]

Finally, solve the resultant force.

[tex]R=\sqrt{R_{v} ^{2} +R_{h} ^{2}} =\sqrt{18.45^{2} +38.05^{2}} =42.29N[/tex]