Sagot :
Answer:
E(X)=110∑10X=1X=110×10(10+1)2=5.5
E(X2)=110∑10X=1X2=110×10(10+1)(20+1)6=38.5
Thus Var(X)=E(X2)−(E(X))2=38.5−5.52=8.25
Standard Deviation = 8.25−−−−√≈2.87
Step-by-step explanation:
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Answer:
E(X)=110∑10X=1X=110×10(10+1)2=5.5
E(X2)=110∑10X=1X2=110×10(10+1)(20+1)6=38.5
Thus Var(X)=E(X2)−(E(X))2=38.5−5.52=8.25
Standard Deviation = 8.25−−−−√≈2.87
Step-by-step explanation:
copy nlng kapagod mag type