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One solution is 60% acid and another one is
10% acid. How much of
each solution is needed
to make 100 gallons that
is 45% acid?


Sagot :

[tex]\large\rm{Answer:}[/tex]

  • 70 gallons of 60% acid and (100 - 70) = 30 gallons of 10% acid

[tex]\large\rm{Solution:}[/tex]

Let us take x gallons of 60% acid

Then,

NO. of gallons of 10% acid = (100 - x)

According to question.

60% × x + 10% × (100 -x) = 45% × 100

[tex]\large\mathsf{ \frac{60}{100}}[/tex]x + [tex]\large\mathsf{ \frac{10(100\:-\:x}{100}}[/tex] = [tex]\large\mathsf{ \frac{45}{100}\:×}[/tex] 100

60x + 1000 - 10x = 45.00

50x = 3500

x = [tex]\large\mathsf{ \frac{3500}{50}x}[/tex]

x = 70