👤
BRETHNEYNEJALIN
Answered

what is the equation of a circle whose center is at the point of origin and touches a point whose coordinates are (-3,-8).​

Sagot :

JADEMATE54IN

Answer:

x^2 + y^2 = 81

One form of writing an equation of a circle is:

(x-h)^2 + (y-k)^2 = r^2

In this form h is the x-coordinate of the center. For this problem h = 0, because the center is at the origin.

In this form k is the y-coordinate of the center. For this problem k = 0.

In this form r is the radius. For this problem r = 9

x^2 + y^2 = 81

In Studier: Other Questions