Answer:
I will solve for percentage composition of
N
in the compound.
Explanation:
Molecular mass of aspartame:
=
(
14
×
12.011
+
18
×
1.00794
+
2
×
14.011
+
5
×
15.999
)
⋅
g
⋅
m
o
l
−
1
=
294.31
g
⋅
m
o
l
−
1
.
But we want the percentage composition of nitrogen in the sample:
2
×
14.011
⋅
g
⋅
m
o
l
−
1
294.31
⋅
g
⋅
m
o
l
−
1
×
100
%
=
?
?
%
Note that the sum of the individual elemental percentages must equal 100%
