Sagot :
GCF(20, 350) = 10
Solution
Set up a division problem where a is larger than b.
a ÷ b = c with remainder R. Do the division.
Then replace a with b, replace b with R and repeat the division.
Continue the process until R = 0.
350 ÷ 20 = 17 R 10 (350 = 17 × 20 + 10)
20 ÷ 10 = 2 R 0 (20 = 2 × 10 + 0)
When remainder R = 0, the GCF is the divisor, b, in the last equation. GCF = 10