Finding the missing term in the proportions.
1. 3 : 5 = N : 50
\begin{gathered} \frac{3}{5} = \frac{n}{50} \\ 5n = 50(3) \\ 5n = 150 \\ n = 150 \div 5 \\ n = 30\end{gathered}
5
3
=
50
n
5n=50(3)
5n=150
n=150÷5
n=30
2. 64 : N = 8 : 9
\begin{gathered} \frac{64}{n} = \frac{8}{9} \\ 8n = 64(9) \\ 8n = 576 \\ n = 576\div 8 \\ n = 72\end{gathered}
n
64
=
9
8
8n=64(9)
8n=576
n=576÷8
n=72
no3. 2/9 = N/81
\begin{gathered} \frac{2}{9} = \frac{n}{81} \\ 9n = 81(2) \\ 9n = 162 \\ n = 162 \div 9\\ n = 18\end{gathered}
9
2
=
81
n
9n=81(2)
9n=162
n=162÷9
n=18
4. 5 : 12 = 35 : N
\begin{gathered} \frac{5}{12} = \frac{35}{n} \\ 5n = 12(35) \\ 5n = 420 \\ n = 420 \div 5 \\ n = 84\end{gathered}
12
5
=
n
35
5n=12(35)
5n=420
n=420÷5
n=84
5. 2 : N = 4 : 18
\begin{gathered} \frac{2}{n} = \frac{4}{18} \\ 4n = 2(18) \\ 4n = 36 \\ n = 36 \div 4 \\ n = 9\end{gathered}
n
2
=
18
4
4n=2(18)
4n=36
n=36÷4
n=9
