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LENYCABANESIN
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6. Find the 27th term of the arithmetic sequence 5,8,11,54,... .7. Find the 40th term of the arithmetic sequence 2,5,8,11,... .8. Find the 16th term in the series 7,13,19,25,... .​

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ANSWERS:

  • 6) 83
  • 7) 119
  • 8) 97

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SOLUTIONS:

➣ Solution for number 6:

Given Series:

5, 8, 11, 54, ...

a = 5, d = 8 - 5 = 3

So, t₂₇ = a + (n - 1)d

= 5 + (27 - 1)(3)

= 5 + 26 × 3

= 83

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➣ Solution for number 7:

Given sequence:

2, 5, 8, 11, ...

Here, First term: a = 2

Number of terms: n = 40

Common difference: d = 3

So, The 40th term is,

t₄₀ = a + (n - 1)d

= 2 + (40 - 1)(3)

= 2 + 39 × 3

= 119

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➣ Solution for number 8:

Given Series:

7, 13, 19, 25, ...

Here, a = 7, d = 13 - 7 = 6

16th term, t₁₆ = a + (n - 1)d

= 7 + (16 - 1)6

= 7 + 90

= 97

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