Answer:
Explanation:
The total voltage is the sum of the individual voltages:
V=V_1+v_2+V_3\\\frac{q}{C_s}=\frac{q}{C_1}+\frac{q}{C_2}+\frac{q}{C_3}V=V
1
+v
2
+V
3
C
s
q
=
C
1
q
+
C
2
q
+
C
3
q
Canceling the Qs, we obtain the equation for the total capacitance in series CS to be
\frac{1}{C_s}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}
C
s
1
=
C
1
1
+
C
2
1
+
C
3
1
An expression of this form always results in a total capacitance CS that is less than any of the individual capacitances C1, C2, …
It tends to zero.
2) Using the relationship Q = CV, we see that the total charge is
C_pV=C_1V+C_2V+C_3VC
p
V=C
1
V+C
2
V+C
3
V
Canceling V from the equation, we obtain the equation for the total capacitance in parallel
C_p=C_1+C_2+C_3C
p
=C
1
+C
2
+C
3
Total capacitance in parallel is simply the sum of the individual capacitances.
