Answer:
8) 2x⁴-x³-6x²
solution
(8x³-4x²-24x)÷4x
make it to fraction
8x³-4x²-24x
_ x
4
factor out 4 from the expression
4(2x³-x²-6x)
_ x
4
remove the 4 outside and the 4 under the fraction
(2x³-x²-6x)x
remove the () and the x outside
= 2x⁴-x³-6x²
9) x - 4
again write the problem in fraction
x²-8x+16
_
x-4
use a²-ab+b²=(a-b) ² to factor the expression
(x-4) ²
_
x-4
simplify the answer, remove the (x-4)² and just put x-4 since they're just the same but with () and a square number
x-4
BUT
if excluded values, this is another answer
(x²-8x+16) ÷(x-4)
to find the excluded values, set the denominators and the divisor equal to 0
x-4=0
remove 0 and replace the - with =
x=4
