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the area of the rectangle is 3ײ +7×+6what is the length if the width is (x+3) ​

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XIAAHIN

PROBLEM:

  • the area of the rectangle is 3x² +7x + 6 what is the length if the width is (x + 3). ​

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ANSWER:

  • [tex]{\large{\underline{\boxed{\sf{\red{Length= (3x-2)}}}}}}[/tex]

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SOLUTION:

[tex]\large{ \tt \red{Given:}}\\\small{ \tt \purple{Area =3x^2+7x+6}}\\\small{ \tt \purple{Width=(x+3)}}\\\small{ \tt \purple{Length:\:?}}[/tex]

[tex]\small{ \tt \purple{3x^2+7x+6}}\\\small{ \tt \purple{3x^2+9x-2x-6}}\\\small{ \tt \purple{3x(x+3)-2(x+3)}}\\\small{ \tt \purple{(3x-2)(x+3)}}\\\\\small{ \tt \purple{The\:width\:is=(x+3)}}\\\small{ \tt \purple{The\:length\:is=(3x-2)}}[/tex]

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