Answer:
61. logx(6) we can rewrite this as logx(2)+logx(3) given the values of logx(2) and logx(3) we can day that 0.3562+0.5646 and that is 0.9208
62. logx(3/2) we can rewrite this as logx(3)-logx(2) and this is 0.5646-0.3562 = 0.2084
63.logx(25) we cab rewrite this as logx(5)+logx(5) and that is 0.8271+0.8271 = 2.8271
64.logx(√2) we can rewrite this as logx(2^1/2) then rewriting again 1/2logx(2) = 1/2(0.3562)= 0.1781
65. logx(1/4)= logx(1)-logx(2) = 0.3562
66.logx(15)= logx(3)+logx(5) = 0.5646+0.8271=1.3917
67.logx(5/3)= logx(5)-logx(3)= 0.2625
68.logx(18)= 3logx(3) or logx(3)^3 = (0.5646)^3= 0.1799
69.logx(30) = logx(3)+logx(5)^2= 1.248
70.logx(40)= logx(5)^8= (0.8271)^8 = 0.219
