Let x and y be the 2 numbers
According to the given , we know that
√( x^2 - y^2) = 4
y = x - 2
or
x = y - 2
Next is we do substitution , lets do y = x-2 first
√[x^2 - (x - 2)^2 ] = 4
x^2 - x^2 + 4x - 4 = 16
4x = 20
x= 5
then find y
y= 5 - 2
y = 3
Next is we do substitute if x = y - 2
√[(y - 2)^2 - y^2] = 4
y^2 - 4y + 4 - y^2 = 16
-4y = 12
y= - 3
Since it says "positive" x= y-2 is not a solution since we got y as negative
so answer ? 5 and 3
