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Add: 2 3/4 + 2/3 =

A. 3 5/12
B. 2 6/7
C. 2 1/3
D. 2 1/4


Sagot :

QUESTION:

2 3/4 + 2/3 =

[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

ANSWER:

A. [tex]\sf\green {5}[/tex][tex]\sf\frac\green {5}\green{12}[/tex]

[tex] \\ [/tex]

SOLUTION:

[tex]\frac {2×4+3}{4}[/tex] + [tex]\frac {2}{3}[/tex]

[tex]\frac {11}{4}[/tex] + [tex]\frac {2}{3}[/tex]

[tex]\frac {11×3}{12}[/tex] + [tex]\frac {2×4}{12}[/tex]

[tex]\frac {33}{12}[/tex] + [tex]\frac {8}{12}[/tex]

[tex]\frac {(33\:+\:8)}{12}[/tex]

[tex]\frac {41}{12}[/tex]

[tex]\frac {3×12+5}{12}[/tex]

= [tex]\sf\green {5}[/tex][tex]\sf\frac\green {5}\green{12}[/tex]

[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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[tex]\sf\pink {{AlexaLexie⚘}}[/tex]

[tex]\large\blue {△☆☂〇}[/tex]

[tex] \begin{gathered} \begin{gathered}\tiny\boxed{\begin{array}{} \red{\bowtie} \:\:\:\:\:\:\: \red{\bowtie}\\ \fcolorbox{color}{violet}{\tt{} > <}\\ \: \smile\end{array}}\end{gathered}\end{gathered} [/tex]

✏️FRACTIONS

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Given: Add 2 3/4 + 2/3

Answer: [tex] \begin{gathered} \Large \underline{\rm{\green{\:A. \:3\frac{5} {12} \:}}} \end{gathered} [/tex]

Solution: Rewrite our equation with parts separated.

  • [tex] \begin{gathered}2 + \frac{3}{4} + \frac{2}{3} \end{gathered}[/tex]

- Solve the fraction parts first.

  • [tex] \begin{gathered} \frac{3}{4} + \frac{2}{3} \end{gathered}[/tex]

- Find the LCD, since the denominators are different. Therefore our LCD is 12.

  • [tex] \begin{gathered} \frac{3 \cdot3}{3 \cdot4} + \frac{2 \cdot4}{3 \cdot4} \end{gathered}[/tex]

  • [tex] \begin{gathered} \frac{9}{12} + \frac{8}{12} \end{gathered}[/tex]

  • [tex] \begin{gathered} \frac{17}{12}\end{gathered}[/tex]

- Since the numerator is the highest number than denominator. We just simplify by dividing 17 by 12.

  • [tex] \begin{gathered} 1\frac{5}{12}\end{gathered}[/tex]

- Combine the whole and fraction parts.

  • [tex] \begin{gathered}2 + 1 + \frac{5}{12}\end{gathered}[/tex]

  • [tex] \begin{gathered}3 \frac{5}{12}\end{gathered}[/tex]

- Therefore, the final answer is:

  • [tex] \large \boxed{ \sf{ \green{ \: 3\frac{5}{12} \: }}}[/tex]

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