Sagot :
QUESTION:
2 3/4 + 2/3 =
[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]
ANSWER:
A. [tex]\sf\green {5}[/tex][tex]\sf\frac\green {5}\green{12}[/tex]
[tex] \\ [/tex]
SOLUTION:
[tex]\frac {2×4+3}{4}[/tex] + [tex]\frac {2}{3}[/tex]
[tex]\frac {11}{4}[/tex] + [tex]\frac {2}{3}[/tex]
[tex]\frac {11×3}{12}[/tex] + [tex]\frac {2×4}{12}[/tex]
[tex]\frac {33}{12}[/tex] + [tex]\frac {8}{12}[/tex]
[tex]\frac {(33\:+\:8)}{12}[/tex]
[tex]\frac {41}{12}[/tex]
[tex]\frac {3×12+5}{12}[/tex]
= [tex]\sf\green {5}[/tex][tex]\sf\frac\green {5}\green{12}[/tex]
[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]
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[tex]\sf\pink {{AlexaLexie⚘}}[/tex]
[tex]\large\blue {△☆☂〇}[/tex]
[tex] \begin{gathered} \begin{gathered}\tiny\boxed{\begin{array}{} \red{\bowtie} \:\:\:\:\:\:\: \red{\bowtie}\\ \fcolorbox{color}{violet}{\tt{} > <}\\ \: \smile\end{array}}\end{gathered}\end{gathered} [/tex]
✏️FRACTIONS
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Given: Add 2 3/4 + 2/3
Answer: [tex] \begin{gathered} \Large \underline{\rm{\green{\:A. \:3\frac{5} {12} \:}}} \end{gathered} [/tex]
Solution: Rewrite our equation with parts separated.
- [tex] \begin{gathered}2 + \frac{3}{4} + \frac{2}{3} \end{gathered}[/tex]
- Solve the fraction parts first.
- [tex] \begin{gathered} \frac{3}{4} + \frac{2}{3} \end{gathered}[/tex]
- Find the LCD, since the denominators are different. Therefore our LCD is 12.
- [tex] \begin{gathered} \frac{3 \cdot3}{3 \cdot4} + \frac{2 \cdot4}{3 \cdot4} \end{gathered}[/tex]
- [tex] \begin{gathered} \frac{9}{12} + \frac{8}{12} \end{gathered}[/tex]
- [tex] \begin{gathered} \frac{17}{12}\end{gathered}[/tex]
- Since the numerator is the highest number than denominator. We just simplify by dividing 17 by 12.
- [tex] \begin{gathered} 1\frac{5}{12}\end{gathered}[/tex]
- Combine the whole and fraction parts.
- [tex] \begin{gathered}2 + 1 + \frac{5}{12}\end{gathered}[/tex]
- [tex] \begin{gathered}3 \frac{5}{12}\end{gathered}[/tex]
- Therefore, the final answer is:
- [tex] \large \boxed{ \sf{ \green{ \: 3\frac{5}{12} \: }}}[/tex]
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