Answer:
Oct 15, 2017
See a solution process below:
Explanation:
For each of the equations solve the equation for two points:
Equation 1:
For
x
=
0
:
(
2
⋅
0
)
+
y
=
1
0
+
y
=
1
y
=
1
or
(
0
,
1
)
For
x
=
2
:
(
2
⋅
2
)
+
y
=
1
4
+
y
=
1
4
−
4
+
y
=
1
−
4
0
+
y
=
−
3
y
=
−
3
or
(
2
,
−
3
)
Equation 2:
For
y
=
0
:
x
+
(
2
⋅
0
)
=
−
2
x
+
0
=
−
2
x
=
−
2
or
(
−
2
,
0
)
For
x
=
0
:
0
+
2
y
=
−
2
2
y
=
−
2
2
y
2
=
−
2
2
y
=
−
1
or
(
0
,
−
1
)
Graph Equation 1 by plotting the two points and drawing a straight line through them:
graph{(x^2+(y-1)^2-0.03)((x-2)^2+(y+3)^2-0.03)(2x + y - 1)=0}
Add the graph Equation 2 by plotting the two points and drawing a straight line through them:
graph{(2x + y - 1)((x+2)^2+y^2-0.03)(x^2+(y+1)^2-0.03)(x+2y+2)=0}
Solution:
graph{(2x + y - 1)(x+2y+2)((x-1.3333333333)^2+(y+1.666666667)^2-0.0025)=0 [-2, 2, -2, 0]}
Or
(
8
3
,
−
5
3
)
