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Answered

Determine the quadratic function y=ax^2+bx+c given the x-intercepts (-2,0) (2,0) and a point (4,2)

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PEARLMILKTEAIN

Answer:

y = 1/6 (x+2)(x-2) or y = [tex]\frac{x^2}{6}-\frac{2}{3}[/tex]

Step-by-step explanation:

y = a(x+2)(x-2)

Substitute point (4,2)

2 = a (4+2)(4-2)

2 = a (6)(2)

2 = 12a

a = 1/6

y = 1/6 (x+2)(x-2) or y = [tex]\frac{x^2}{6}-\frac{2}{3}[/tex]

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