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A yaya receives a starting annual salary of php 6000 with a yearly increase of php 3,600 what is her total income for 5 years

Sagot :

Answer:

Solution:

1st Year:     Php 6,000

2nd Year:    Php 6,000  + Php 3, 600 = Php 9, 600

3rd Year:    Php 9, 600 + Php 3, 600 = Php 13, 200

4th Year:     Php 13, 200 + Php 3, 600 = Php 16,800

5th Year:    Php 16, 800 + Php 3, 600 = Php 20, 400

Computation:

      6 000

  +  9 600

  + 13 200

  + 16 800

 + 20 400

    66 000

Final Answer:

Php 66, 000

Step-by-step explanation:

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