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Answered

what are the zereos of p(x)=x3-6x2-x+6

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ANONYMOUSBETAIN

x^3 - 6x^2 - x + 6 = 0

x^2 (x - 6) - (x - 6) = 0

(x^2 - 1) (x - 6) = 0

(x-1)(x+1)(x-6) = 0

x= +/-1 , x= 6

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