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3 is the remainder when 2x³+5x²–4x+16 is divided by x+3?​

Sagot :

ANSWER:

No, the remainder is 19.

EXPLANATION:

We can check this using the remainder theorem.

"The remainder theorem is stated as follows: When a polynomial a(x) is divided by a linear polynomial b(x) whose zero is x = k, the remainder is given by r = a(k)."

Now, given:

  • a(x) = 2x³+5x²–4x+16
  • b(x) = x + 3

Equate x + 3 to 0 and solve for x.

  • x + 3 = 0
  • x = -3

Substitute the value of x to a(x) and solve.

  • a(x) = 2x³+5x²–4x+16
  • a(-3) = 2(-3)³ + 5(-3)² - 4(-3) + 16
  • a(-3) = 2(-27) + 5(9) + 12 + 16
  • a(-3) = -54 + 45 + 12 + 16
  • a(-3) = 19
  • r = 19
  • The remainder is 19.