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Find the next three terms of the geometric sequence 3,21,147​

Sagot :

Just multiply by 7 example

3

3x7 =21

21x7=147

147x7=1029

Answer:

[tex]r = \frac{a2}{a1} \\ r = \frac{21}{3} \\ r = 7[/tex]

[tex]a4 = a3r \\ a4 = (147)(7) \\ a4 = 1029[/tex]

[tex]a5 = (1029)(7) \\ = 7203[/tex]

[tex]a6 = (7203)(7) \\ = 50421[/tex]

Therefore, the next three terms are 1029, 7203, and 50421.