Answer:
(3ײ-×)+(ײ+12×-5)+(2ײ+7) = [tex]6x^2+11x+2[/tex]
Step-by-step explanation:
simplify: (3ײ-×)+(ײ+12×-5)+(2ײ+7)
[tex]=3x^2-x+x^2+12x-5+2x^2+7[/tex]
[tex]Group\:like\:terms[/tex]:
[tex]=3x^2+x^2+2x^2-x+12x-5+7[/tex]
[tex]\mathrm{Add\:the\:numbers:}\:-5+7=2[/tex]
[tex]=3x^2+x^2+2x^2-x+12x+2[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:3x^2+x^2+2x^2=6x^2[/tex]
[tex]=6x^2-x+12x+2[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:-x+12x=11x[/tex]
[tex]=6x^2+11x+2[/tex]
so the answer is [tex]=6x^2+11x+2[/tex]
