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Answered

Determine how much heat, in joules, must be added to a 5.00 × 102- g copper pan to change its temperature from 25 °C to 250 °C? The specific heat of copper iron is 0.385 J/g °C

Sagot :

SYDLAG10196IN

Answer:

433125 J or  4.33 × 10^5 J

Explanation:

Q = mc∆T

Q = (5.00 × 10² g)(0.385 J/g°C)(250°C - 25°C)

Q = (1.925J°C)(225°C)

Q= 433125 J or 4.33 × 10^5 J

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