GEOMETRIC SEQUENCE
» Find the five terms of geometric sequence where the first term is 7 in the common ratio is 6.
Given:
- [tex]a_{1} = 7[/tex]
- [tex]r = 6[/tex]
- Since r = 6, just multiply 6 to the previous term to obtain next term.
Solution:
[tex] a_{1} = 7\\ a_{2} = 7(6) = 42\\ a_{3} = 42(6) = 252\\a_{4} =252 (6) = 1512\\ a_{5} = 1512(6) = 9072[/tex]
Answer:
- The first five terms of the geometric sequence whose a1 = 7 and r = 6 is 7, 42, 252, 1,512, and 9,072.
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